5q^2+13q+8=0

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Solution for 5q^2+13q+8=0 equation: 



5q^2+13q+8=0

a = 5; b = 13; c = +8;
Δ = b2-4ac
Δ = 132-4·5·8
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$


$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-3}{2*5}=\frac{-16}{10}
=-1+3/5
$


$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+3}{2*5}=\frac{-10}{10}
=-1
$

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